Testing Diodes

First of all, we had to identify the direction of flow through the diode. This is done by 1: Visual inspection of the diode itself shows that one end is painted which shows that it is the cathode end and 2: By measuring the resistance on each side it shows that when it is one way round it will read infinity as there is no flow through, and the other will have a high reading which means it is the anode end.
We had to then measure the resistance of the diode in both directions using the 2K ohms position on the meter:
Anode to Cathode: Infinity
Cathode to Anode: Infinity
It was said that both of these readings were going to read infinity as there should be no resistance within the diode. The voltage supplied was 0.05v which means theoretically there is not enough voltage to push through the bindery layer of the diode and get an accurate reading.

We then had to measure the diode in both directions:
Anode to Cathode: 0.683v
Cathode to Anode: Infinity
Explain what the Diode Test Position readings means when you test the diode in both directions and describe whether the diode was good or bad:
The diode is in good condition as it shows the amount of voltage allowed through in one direction. The other however has no reading, which is as it should be.

After building a circuit with a 1K ohm diode and a resistor, using a 12 volt supply.
Voltage drop across resistor: 13.22v
Voltage drop across the diode: 0.57v
Measure amp flow through the diode: 0.01A
Avaliable voltage at voltage supply: 13.8v
Voltage drop (sum) across the resistor and diode: 13.79v

Apply the rules of Electricity to these readings above and describe how these readings demonstrate the rules of electricity in action:
As voltage is quite high and so is the resistance, there appears to be verylow to minimal amps in the circuit. The resistor, being large allows very little voltage through, so the remainder of voltage in the circuit is below 1v. The diode had a voltage drop of 0.57v which is the remainder of voltage in the circuit. No voltage left as it grounds.

After changing the resistor in the circuit to a 4000 ohm resistor:
Voltage drop across resistor: 13.28v
Voltage drop across diode: 0.5v
Amp flow through D: 0.01A
Describe how this change of resistance lead to changes in your volt and amp readings. Discuss how this demonstrates how the rules of electricity work.
The readings did not change much, if at all,

After testing an LED (Light Emitting Diode):
Anode to Cathode: 1.834v
Cathode to Anode: Infinity
Compare the voltage drop of a normal diode and an LED. What does this tell you?
1.88v of LED, 0.5v for normal resistor. LED needs more voltage to energise it.

We then had to build a circuit with an LED in the diode position with a 1K ohm resistor and a 12v power supply.
Voltage drop across the resistor: 11.77v
Voltage drop across the diode: 1.88v
Amp flow through LED: 0.01A
Avaliable voltage at voltage supply: 13.5v
Voltage drop (sum) of resistor + diode: 13.65v
Apply the rules of electricity to these readings and compare how these readings are different than the readings for the diode above. In other words, how does the difference between a diode and an LED result in different readings for each part? Explain:
The voltage drop of the resistor decreases as more voltage is needed for the LED. The amp reading is still very low though.